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14.4t^2-6t=0
a = 14.4; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·14.4·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*14.4}=\frac{0}{28.8} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*14.4}=\frac{12}{28.8} =3/7.2 $
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